How to identify redundant/duplicate indexes in SQL Server

What are redundant indexes in SQL Server?

Identifying redundant indexes is a very important task for a DBA. I personally do not find any reason of having redundant indexes on databases. Otherwise, it is an over head to the system like maintaining the index/storage space etc.

The challenge is to identify a redundant/duplicate index in SQL Server? If we do not understand the meaning of redundant/duplicate, then we might end up with removing important indexes and it can lead to performance degradation.

I would like to list out few considerations to categorize indexes as redundant; if:

1. An index has Same key columns in the same order with another index

2. An index has Key columns those are left based subset of another index

3. Meeting all of the above, ONLY for similar index types.(Clustered and no clustered are not to be considered as duplicate indexes)

4. Meeting all of the above, And the Key Columns specified with same ordering (ASC/DESC)

The below query does not identify the duplicate index, but it gives you enough information with which we can easily identify the duplicate indexes in your system.

Note:(String_AGG is new function in SQL Server 2017)

Select Object_Schema_name(ix.object_id) Schema_Name,
		Object_name(ix.object_id) Object_Name,ix.name,ix.type_desc ,
		string_agg(Cast(c.name as nvarchar(MAX)) + ' (' + case when is_descending_key = 0  then 'ASC' Else 'DESC' END + ') ',',') 
		within group(Order by ixc.key_ordinal asc) As KeyCols
From
	sys.indexes ix
	inner join sys.index_columns ixc on ix.index_id = ixc.index_id and ix.object_id = ixc.object_id
	inner join sys.columns c on ixc.object_id = c.object_id and c.column_id = ixc.column_id 
Where objectpropertyex(ix.object_id,'IsMSShipped') =0 
		And ixc.is_included_column=0 and ix.index_id <> 1 
		Group by ix.object_id,ix.name,ix.type_desc
Order by 1 asc,2 asc

Iā€™d like to grow my readership. If you enjoyed this blog post, please share it with your friends!

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Google photo

You are commenting using your Google account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s